get

k=[ ]; for i in range(1,101,1): k.append(i*i) print(k); n=0; for j in range(0,99): n=k[j]+n; print(n);

``` i = [] for j in range(1, 101): k = j * j i += [k] j += 1 print(i) x = 0 for m in range(1,101): n = m * m x += n print(x) ```

returnlist=[k*k for k in range(1,101)] print(returnlist) print(sum(returnlist))

Traceback (most recent call last): File "/tmp/jqcore/jqboson/jqboson/core/entry.py", line 368, in _run engine.start() File "/tmp/jqcore/jqboson/jqboson/core/engine.py", line 231, in start self._dispatcher.start() File "/tmp/jqcore/jqboson/jqboson/core/dispatcher.py", line 273, in start self._run_loop() File "/tmp/jqcore/jqboson/jqboson/core/dispatcher.py", line 240, in _run_loop self._loop.run() File "/tmp/jqcore/jqboson/jqboson/core/loop/loop.py", line 105, in run self._handle_queue() File "/tmp/jqcore/jqboson/jqboson/core/loop/loop.py", line 151, in _handle_queue message.callback(**message.callback_data) File "/tmp/jqcore/jqboson/jqboson/core/dispatcher.py", line 110, in callback self._event_bus.emit(evt) File "/tmp/jqcore/jqboson/jqboson/core/bus.py", line 47, in emit ret.append(call(event)) File "/tmp/jqcore/jqboson/jqboson/core/strategy.py", line 376, in _wrapper return cb(self._context.strategy_environment.strategy_context, **cb_kwargs) File "/tmp/strategy/user_code.py", line 45, in market_open MA5 = close_data['close'].mean() KeyError: 'close'

@wp0720 这是什么意思呢？

list=[] sum=0 for i in range(1,101): list.append(i**2) print(list) for i in list: sum +=i print(sum)

@hubert_cao 精简！这才是python的魅力

a = [] for i in range(100): a.append ((i+1)**2) print(a) j = 0 for i in range(len(a)): j+=a[i] print(j) 

打卡

打卡

a=[] a=list(range(1,101)) print(a) b=np.array(a) print(b**2)

琢磨了一个下午，原来可以如此简单 a=[] a=list(range(1,101)) for i in range(len(a)): a[i]=a[i]**2 print(a)

#排序2 b = [4,2,1,9,6,5,3,8,7] b.sort() b.reverse() print(b) 关于排序那个为何要写那么复杂？

for i in range(1,100): j=i**2 print(j)

``` code ```for i in range(1,100): j=i**2 print(j)



 ------------------------------------------------ 当触发止损时，cost会变为0，这时cost不能作为除数 所以加入一个判断cost是否为零的条件