作业2&3 list=[b*b for b in range(1,101,1)] print(list) sum=0 for j in range(1,101,1): sum += j*j print(sum)

学习了！

xiexxi谢谢指教，已学习

取平方和求和 list_a =range(1:101) list_square_a=[] for i in list_a: list_square_a.append(i**2) print(list_square_a) print(sum(list_square_a)) 代码运行的结果是把list里面数字从小到大排列了 a = [1,2,3,4,5,6,7,8,9]

``` # 导入函数库 from jqdata import * # 初始化函数，设定基准等等 def initialize(context): print(getListSqure(context)) print(getListValue(context)) def getListSqure(context): ltRet=[] for i in range(1,101,1): ltRet.append(i*i) return ltRet def getListValue(context): iRet = 0 for i in getListSqure(context): iRet += i return iRet ```

list_1 = [ ] for i in range ( 101 ) : list_1.append ( i*i ) print ( list_1 )

学习了

list_1=[] for i in range(101): list_1.append(i**2) sum=0 for j in list_1: sum=j+sum print(sum)

@太阳花小叶子 第2行应该是for i in range(1,101):

打卡

``` def initialize(context): run_daily(period, time='every_bar') g.security=['000001.XSHE','000002.XSHE'] def period(context): for gp in g.security: time=context.current_dt.strftime('%Y-%m-%d') if time=='2017-03-01': order(gp,100) if time=='2017-03-21': order_target(gp,0) cost=context.portfolio.positions[gp].avg_cost#持仓均价 price=context.portfolio.positions[gp].price#最新价 print('成本价:%s'% cost) print('现价：%s'% price) if cost!=0: ret=price/cost-1#收益率 print('收益率:%s'%ret) if ret< -0.1: order_target(gp,0) print('触发止损') elif ret>0.2: order_target(gp,0) print('触发止盈') ```

for t in range(1,1,101): g.a[t-1]=t*t for t in range(1,1,101): print(g.a(t-1))

这基础教程不错

``` def initialize(context): run_daily(period,time='every_bar') # 把两个股票代码作为list存入g.security中 g.security = ['000001.XSHE','000002.XSHE'] def period(context): for stk in g.security: order(stk,100) # 获得股票持仓成本 cost=context.portfolio.positions[stk].avg_cost # 获得股票现价 price=context.portfolio.positions[stk].price # 计算收益率 ret=price/cost-1 # 如果收益率小于-0.01，即亏损达到1%则卖出股票，幅度可以自己调，一般10% if ret< -0.01: order_target(stk,0) print('触发止损') ``` 运行这段代码，会出现ZeroDivisionError: division by zero 有点迷茫了

计算ret 要保证分母不等于0 在这句前加if cost != 0:

g.security = ['000001.XSHE','000002.XSHE']只能一个个添加吗？请教下可以在中括号里面放一个函数吗？我尝试过失败了。。。

@Mosigan 因为回测时间缺省是从2016-06-01开始的，而这个时间万科停牌，因此下单失败，导致cost为0，把回测时间改到2016-07-04以后就可以了

[ i \* i for i in range(1,101)] sum([ i \* i for i in range(1,101)])

import numpy as np list1 = [i+1 for i in range(100)] np_list = np.array(list1) np_list = np_list**2 result = 0 for i in np_list: result += i print(result)