搞明白了，每一次将剩余部分最大的数调整到最前面来。

很好

打卡学习

卡萨丁黑客技术均安抵扣均安货款收打算打

@Zouk 相互学习得积分

@chrispaulmvp 学习

冒泡法

很好

learning

学习

338350 k = [i**2 for i in range(1,101)] 降序

for k in range(1,101): a=k*k print(a)

a=0 for k in range(1,101): a=k*k+a print(a)

``` a = [] b = 0 for i in range(1,101): a.append(i**2) b += i**2 print(a) print(b) ``` ``` 2019-01-01 00:00:00 - INFO - [1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144, 169, 196, 225, 256, 289, 324, 361, 400, 441, 484, 529, 576, 625, 676, 729, 784, 841, 900, 961, 1024, 1089, 1156, 1225, 1296, 1369, 1444, 1521, 1600, 1681, 1764, 1849, 1936, 2025, 2116, 2209, 2304, 2401, 2500, 2601, 2704, 2809, 2916, 3025, 3136, 3249, 3364, 3481, 3600, 3721, 3844, 3969, 4096, 4225, 4356, 4489, 4624, 4761, 4900, 5041, 5184, 5329, 5476, 5625, 5776, 5929, 6084, 6241, 6400, 6561, 6724, 6889, 7056, 7225, 7396, 7569, 7744, 7921, 8100, 8281, 8464, 8649, 8836, 9025, 9216, 9409, 9604, 9801, 10000] 2019-01-01 00:00:00 - INFO - 338350 ```

``` list = [] for i in range(1,101): a = i*i list.append(a) print(f'100项的平方数列：{list}') b = 0 for i in list: b = b + i print(f'100项的平方数数列的和：{b}') ```

a=[t**2 for t in range(1,101)] print(a) b=0 for a in range(1,101): b=b+a**2 print(b)

学习打卡，走上量化投资之路！

a = [] for b in range(1,101,1): a.append(b**2) print(a) num = 0; for c in a : num = num + c print(num)

感谢分享